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Reduced risk of pneumonia after changes in anesthetic procedures for dogs receiving repeated anesthesia for radiation treatment
- Baetge, Courtney, Cummings, Kevin J., Deveau, Michael
- Veterinary radiology & ultrasound 2019 v.60 no.2 pp. 241-245
- anesthesia, anesthetics, body weight, comorbidity, dogs, equipment, medical records, megaesophagus, nausea, neoplasms, observational studies, odds ratio, patients, pneumonia, radiotherapy, regression analysis, risk, risk reduction
- Radiation therapy requires repeated anesthetic administration to patients who often have multiple comorbidities contributing to an increased rate of anesthetic complications such as pneumonia. This is a retrospective observational study in which data were collected from 146 medical records of dogs receiving repeat anesthesia for radiation treatment from prior to management changes and compared to data from 149 cases treated after completion of management changes. The objective was to determine if changes in case management protocol that were put in place decreased the risk of pneumonia development among these patients. Management changes that were made included the following: decrease in anticholinergic and pure‐mu opioid use, change in positioning during intubation and recovery, prophylactic treatment of nausea, timing of cuff inflation and deflation, and aseptic handling of intubation equipment. There was a significant association between diagnosis of pneumonia and the following: pre‐ vs. post‐changes to protocol, presence of a neurologic tumor, presence of respiratory disease, presence of megaesophagus, and number of radiation fractions completed. Diagnosis of pneumonia did not vary significantly by age group, body weight category, or sex. In a multivariable logistic regression model that controlled for the effects of the three concurrent diseases and fractions completed, the odds of being diagnosed with pneumonia were approximately 10 times greater among dogs anesthetized prior to management changes (odds ratio = 9.9, 95% CI = 2.0–48.7, P = 0.005).